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erica [24]
3 years ago
8

What is the equation of a circle with center (8, 6) and radiuss5?

Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

4

Step-by-step explanation:

(8,6,4)

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A circle with a radius of 3cm sits inside a 8cm*7cm rectangle. What is the area of the shaded region? Round your final answer to
Elanso [62]

Answer:

27.73 cm squared

Step-by-step explanation:

In order to find the shaded region, we need to find the areas of the circle and the rectangle and then subtract the circle area from the rectangle area.

The area of a rectangle is denoted by: A = lw, where l is the length and w is the width. Here, the length is l = 7 and the width is w = 8. Plug these in:

A = lw

A = 7 * 8 = 56 cm squared

The area of a circle is denoted by: A = πr², where r is the radius. Here, the radius is r = 3, so plug this in:

A = πr²

A = π * 3² = 9π ≈ 28.27 cm squared

Now subtract 28.27 from 56:

56 - 28.27 = 27.73

The answer is thus 27.73 cm squared.

7 0
3 years ago
Read 2 more answers
The greatest comen factor of 21, 30,49
liq [111]
The greatest common factor for 21 is 7
For 30 is 15
49 is 7

I’m no totally sure but i think that is right
4 0
3 years ago
An olympic hurdler accelerates at a rate of 15.5 m/s2 . what is the rate in miles/min2 ? 1. 6.89 miles/min2 2. 31.8 miles/min2 3
Tom [10]
For this case we have to take into account the following conversions:
 1 mile = 1609.34 meters

1 minute = 60 seconds
 Let's first transform the expression to miles per seconds squared:
 (15.5) * (1 / 1609.34) = 0.009631277 mi / s ^ 2

 Then, we transform the result to miles per minute squared.
 We have then:
 (0.009631277) * (60) ^ 2 = 34.7 mi / min ^ 2

 Answer:
 
the rate in miles/min^2 is:
 
34.7 mi / min ^ 2
3 0
3 years ago
Twenty-six out of 50 teachers drive their cars to school. Approximately what percent of these teacher drive to school
Mars2501 [29]

Answer:

52%

Step-by-step explanation:

26÷50×100

that's it, hope it's okay

4 0
3 years ago
Find the length of side X
NISA [10]

Answer:

C

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the 2 other sides, that is

x² + 6² = 17²

x² + 36 = 289 ( subtract 36 from both sides )

x² = 253 ( take the square root of both sides )

x = \sqrt{253} → C

7 0
3 years ago
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