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Elodia [21]
3 years ago
13

Nathan drew a scale drawing of a house he use the scale 5 cm equal 3 m if the actual length of the garage is 12 m how long is th

e garage in the drawing
Mathematics
1 answer:
never [62]3 years ago
4 0
In the drawing the garage is 7.2 cm
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Select all the expressions that equal.. *see picture for problem* ​
kupik [55]

Answer:

Step-by-step explanation:

oknjbgfkdfrgn jnfbfl

7 0
3 years ago
Item 2<br> Question 1<br> Solve 6x≥−42. Graph the solution.
o-na [289]

Answer:

x ≥ -7

Step-by-step explanation:

Divide both sides by 6

Then to graph it, you can make a number line

8 0
3 years ago
Read 2 more answers
Will mark as brainliest (must show work)
Sever21 [200]

Answer:

46

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW  then

m < XVY = m < YVW

      2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

      2x-x = 15-7, combine like terms

           x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY =  2x+7  = 2*8 +7 = 16 +7 = 23

m < YVW =  x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0
2 years ago
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

6 0
3 years ago
Substitute for p and solve for r.
schepotkina [342]
P is being divided with r
4 0
4 years ago
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