Which of the following is NOT a rational number?

Mathematics

1 answer:

scoray [572]3 years ago

5 0

I think it might be D

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This is function notation and I have no idea how to do it. I need answers.

pashok25 [27]

Answer:

So you are given the function, f(x) = 3x - 4. You will plug in the value given and solve and write the answer down in the box.

f(x) = 3x - 4 ---> f(5), f(2), f(1), f(10), and f(-1) value given

f(5) = 3(5) - 4

f(5) = 15 - 4

f(5) = 11

f(2) = 3(2) - 4

f(2) = 6 - 4

f(2) = 2

f(1) = 3(1) - 4

f(1) = 3 - 4

f(1) = -1

f(10) = 3(10) - 4

f(10) = 30 - 4

f(10) = 26

f(-1) = 3(-1) - 4

f(-1) = -3 - 4

f(-1) = -7

*Answers are bolded.*

Hope this helps, thank you :) !!

6 0

2 years ago

What is the slope of the line shown in the graph? 1) -1 2) -2 3) -1/2 4) 2

Travka [436]

I believe it would be -2 since you use rise over run. That would be -2/1

6 0

2 years ago

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$