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Sergeu [11.5K]
3 years ago
8

Find the maximum volume of a box that can be made by cutting out squares from the corners of an 8-inch by 15-inch rectangular sh

eet of cardboard and folding up the sides.
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
<span>Answers: V = (15-2x)(8-2x)x V = 120x -46x²+ 4x³ V' = 120 -92x + 12x² 0 = 120 -92x + 12x² x = (92±52)/24 x = 6 or 5/3 Pick x = 5/3 Volume = (15-2*5/3)(8-2*5/3)*5/3 = 90.74 in³ To justify x = 5/3 is the max V" = -92 + 24x V"(5/3) = -92 + 24(5/3) <0 negative. Volume V(5/3) is max because the function is concave down with V"<0.</span>
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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
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X = advance 
y= same day 

x+y=70

30x+15y=1650

--------------------------
  30x+15y=1650    
- x+y=70               (x15) -> 15x+15y=1050
--------------------------
 30x+15y=1650 
-15x+15y=1050
--------------------------
15x=600
x=600/15
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so now u can insert the price of x AKA the price of the advanced ticket to find our the price of the same day ticket. 

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x = advance =40
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