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Oxana [17]
3 years ago
8

In a money bag there are equal number of 2p, 5p And no other coins. How many coins are they in the bag if all together there is

£126.00
Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

1800

Step-by-step explanation:

£126=12600 pence

so 5p+2p=7p

12600/7=1800

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A piece of paper is 11 inches long and 8.5 inches wide. What is the area of the paper in square centimeters? (Please show work!)
goldenfox [79]
If you would like to know what is the area of the paper in square centimeters, you can calculate this using the following steps:

1 inch equals to 2.54 centimeters.

11 inches = 11 * 2.54 = <span>27.94 centimeters long
8.5 inches = 8.5 * 2.54 = </span><span>21.59 centimeters wide

11 inches long * 8.5 inches wide = 27.94 centimeters long * 21.59 centimeters wide = </span>27.94 * 21.59 = 603.22 square centimeters
<span>
The correct result would be </span>603.22 square centimeters.<span>
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Sharon has a coupon for $5 off light bulbs at Lowes. The light bulbs she wants cost $7.50 a package. How much money, m, will she
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Sharon would spend $2.50 for the light bulbs she wants.
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Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

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