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Sonbull [250]
3 years ago
15

a certain shark has triangular teeth with a height that is 1 centimeter shorter than the base. if the area of one tooth is 1 squ

are centimeters, find its base and height.
Mathematics
1 answer:
Advocard [28]3 years ago
6 0

The Shark's teeth has a base of 2 cm and height of 1 cm.

Step-by-step explanation:

Step 1 :

Given,

the area of the shark's triangular teeth = 1 sq cm

Let b be the base and h be the height of the shark's triangular teeth.

We have the teeth's height is 1 cm short than the base

So  h = b - 1

Step 2 :

Area of Triangle  = (\frac{1}{2}) × b × h = 1

Substituting h = b -1

(\frac{1}{2}) × b × (b-1) = 1

=> b² - b = 2 = > b²-b-2 = 1

Solving for b we have

(b-2)(b+1) = 0

b = 2 or b = -1

Since b is the base , we take the positive value as length/distance cannot be negative.

So b = 2

h = b - 1 = 2 - 1 = 1

h = 1

Step 3 :

Answer :

The Shark's teeth has a base of 2 cm and height of 1 cm.

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An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

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What is the value of x?
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Answer:

x = 12

Step-by-step explanation:

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2x^3 + 3x^2 -11x -6 divided by x - 2
Gnesinka [82]

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

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therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

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      = 16 + 12 - 22 - 6

      = 28-28

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Hope it helped u, ^_^.

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