The graph of a logarithmic has a vertical asymptote at x=4 , contains the point (e+4, 1) , and has an x-intercept of 5. Which fu
nction is graphed?
Question options:
f(x) =ln(x−4)
f(x) =ln(x+4)
f(x) =lnx−4
f(x) =lnx+4
Question options:
f(x) =ln(x−4)
f(x) =ln(x+4)
f(x) =lnx−4
f(x) =lnx+4
1 answer:
Answer:
f(x) =ln(x−4)
Step-by-step explanation:
We can easily solve this question by plotting each of the graphs and verify the conditions in the problem,
Please see attached image.
The answer is the first option
f(x) =ln(x−4)
Which corresponds to the function ln(x) shifted four units to the right.
Besides,
f(e+4) =ln(e + 4−4) = ln(e) = 1
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