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Tanzania [10]
2 years ago
13

Answer this question! i’ll give brainliest

Mathematics
2 answers:
saw5 [17]2 years ago
6 0

the correct answer is option C

Because if u simplify the 13/3 it would be 4 1/3 and 1/3 is larger than 1/5

Alexeev081 [22]2 years ago
4 0

Answer:

Step-by-step explanation:

A

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Part 4. NO LINKS!! Find the area of the shaded area shown. SHOW WORK PLEASE !! #21​
SIZIF [17.4K]

Area of square

  • 32²
  • 1024

Radius of each circle

  • 32/4/2
  • 8/2
  • 4

Area of 16 circles

  • 16πr²
  • 16π(4)²
  • 16π(16)
  • 256π
  • 803.8cm²

Area of shaded region

  • 1024-803.8
  • 220.2cm²
5 0
2 years ago
Read 2 more answers
The basic sticker price on Mr. Feldman's new car was $3200, The options he desired cost an additional $1800. What percent of the
Keith_Richards [23]
3200 plus 1800 is 5000.
So find the percentage of 5000 1800 is.
So 36%
6 0
3 years ago
Drag and drop each pair of lines to categorize them as either parallel, perpendicular, or neither.
miss Akunina [59]
Answer:
first box is parallel
Second box perpendicular
Third box neither
Fourth box neither
Fifth box perpendicular
Sixth box is parallel

Why? Slopes of parallel lines are the same. Slopes of perpendicular lines are opposite reciprocals. (Example slope=1/2 a perpendicular line would be -2/1). Neither is just a when it’s not either parallel or perpendicular.

Hope this helps
8 0
2 years ago
You are making sets of pens and pencils to sell. You want each set to contain the same combination of pens and pencils. You have
harkovskaia [24]
The greatest number of the sets you can make are 32 sets 
5 0
3 years ago
two pumps of different sizes, working together, can empty a fuel tank in 3 hours. the larger pump can empty the tank in 4 hours
bonufazy [111]
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour. 


8 0
3 years ago
Read 2 more answers
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