3 is in the hundred millions
Part A:
Yes, the data represent a function because there is at least one x-value for every y-value.
Part B:
When x=6 in the input-output table, y=14. When x=6 in the relation f(x)=7x-15, f(x)=7(6)-15=27. <span>The equation has a greater value when x=6.
Part C:</span>
Set f(x) equal to 6 in the equation:
6=7x-15
Solve for x:
7x=21
x=3
<span>x=3 when f(x)=6</span>
Answer:
The proportion of this group that likes chocolate is 0.625.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Likes sprinkles
Event B: Likes chocolate
25% of your friends who like Chocolate (C) also like sprinkles (S).
This means that 
40% of your friends like sprinkles (S) topping.
This means that 
Of the friends who like sprinkles, what proportion of this group likes chocolate

The proportion of this group that likes chocolate is 0.625.
5/8 = .625 width
2 ( l + w ) = 2 ( 0.625+ 2.4) = 2 (3.025) = 6.05
Hop I become the brainiest
Analysis:
1) The graph of function f(x) = √x is on the first quadrant, because the domain is x ≥ 0 and the range is y ≥ 0
2) The first transformation, i.e. the reflection of f(x) over the x axis, leaves the function on the fourth quadrant, because the new image is y = - √x.
3) The second transformation, i.e. the reflection of y = - √x over the y-axis, leaves the function on the third quadrant, because the final image is - √(-x). This is, g(x) = - √(-x).
From that you have, for g(x):
* Domain: negative x-axis ( -x ≥ 0 => x ≤ 0)
* Range: negative y-axis ( - √(-x) ≤ 0 or y ≤ 0).
Answers:
Now let's examine the statements:
<span>A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0
B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0
C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.
D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.
E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.
F)The range of g(x) is all values less than or equal to 0.
TRUE: it was proved above.</span>