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Leviafan [203]
3 years ago
15

The graph of f(x) =(square root of "x") is reflected across the x-axis and then across the y-axis to create the graph of functio

n g(x). Which statements about the functions f(x) and g(x) are true? Check all that apply.
A)The functions have the same range.
B)The functions have the same domains.
C)The only value that is in the domains of both functions is 0.
D)There are no values that are in the ranges of both functions.
E)The domain of g(x) is all values greater than or equal to 0.
F)The range of g(x) is all values less than or equal to 0.
Mathematics
2 answers:
777dan777 [17]3 years ago
5 0

Answer:

C, F.

Step-by-step explanation:

Those are the correct answers on edge.

vesna_86 [32]3 years ago
4 0
Analysis:

1) The graph of function f(x) = √x is on the first quadrant, because the domain is x ≥ 0 and the range is y ≥ 0

2) The first transformation, i.e. the reflection of f(x) over the x axis, leaves the function on the fourth quadrant, because the new image is y = - √x.

3) The second transformation, i.e. the reflection of y = - √x over the y-axis, leaves the function on the third quadrant, because the final image is - √(-x). This is, g(x) = - √(-x).

From that you have, for g(x):

* Domain: negative x-axis ( -x ≥ 0 => x ≤ 0)

* Range: negative y-axis ( - √(-x) ≤ 0 or y ≤ 0).

Answers:

Now let's examine the statements:

<span>A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0

B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0

C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.

D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.

E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.

F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.</span>
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Step-by-step explanation:

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a snowball is rolled down a giant hill. the radius of the snowball grows. every second the radius increases by 0.36 inches. four
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Based on the fact that the radius of the snowball increases by 0.36 inches every second, the linear function can be found to be y = 0.36x + 1.66

<h3>How to find the linear function?</h3>

The linear function is the function that shows how to change in the rate of the independent variable would affect the rate of change in the dependent variable.

The linear function takes the form:

y = mx + b

y = dependent variable

m = slope or change in radius of snowball

x = seconds

b = y-intercept

Solving for the y-intercept gives:

3.1 = 0.36(4) + b

b = 3.1 - 1.44

= 1.66

The linear function is therefore:

y = 0.36x + 1.66

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The scatter plot shows the number of absences in a week for classes of different sizes. Trevor concluded that there is a positiv
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2 years ago
Write the relation as a set of on rdered pai
kirill115 [55]

The relation as a set of ordered pairs is d. {(–2, 1), (0, -1), (2, -3)}.

Step-by-step explanation:

Step 1:

First, we plot the three points on the given graph.

The coordinates are given in the following form (x coordinate, y coordinate) where the symbol of the coordinates depends on the quadrant on which the point lies.

For the first quadrant, both x and y values are positive.

For the second quadrant, the x value is negative but the y value is positive.

For the third quadrant, both the values of x and y are negative.

For the fourth quadrant, the x value is positive but the y value is negative.

Step 2:

The first point has an x value of 2 and a y value of 1 since it is in the second quadrant, the coordinates are (-2, 1).

The second point has an x value of 0 and a y value of 1 since it is in the third or fourth quadrant, the coordinates are (0, -1).

The third point has an x value of 2 and a y value of 3 since it is in the fourth quadrant, the coordinates are (2, -3).

So the coordinates are {(–2, 1), (0, -1), (2, -3)} which is option d.

6 0
3 years ago
If $25, 000 is invested into an account paying 4.5% per year, compounded quarterly, how much money can be withdrawn from the acc
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The money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

<h3>What is compound interest?</h3>

The formula for compound interest is given as;

A = P ( 1 + \frac{r}{n} )^n^t

P = principal interest = $25, 000

r = rate = 4. 5%

n = 2 months

t = 6 years

A = 25, 000 ( 1 + \frac{4. 5}{2} )^2 ^*^6

A = 25, 000(1 + 0. 75)^1^2

A = 25, 000( 825. 00)

A = $20, 625, 000

Thus, the money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

Learn more about compound interest here:

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7 0
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