<h3>
Answer:</h3>
4.7 × 10²⁴ atoms Li
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
7.8 mol Li
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>We are told to round to 2 sig figs. Follow sig fig rules and round.</em>
4.69716 × 10²⁴ atoms Li ≈ 4.7 × 10²⁴ atoms Li
When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE = M g H
we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s
Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.
Explanation:
1) Molarity of 0.250 L HCl solution : 0.0328 M

Moles of HCl in 0.250 L solution = 0.0082 moles
2) Molarity of 0.100 L NaOH solution : 0.0245 M

Moles of NaOH in 0.100 L solution = 0.00245 moles
3) Concentration of hydrochloric acid in the resulting solution.
0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.
Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L
Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

Molarity of HCl left un-neutralized :
0.0164 molar concentration of hydrochloric acid in the resulting solution.
Explanation:
option A is the correct answer of this question
<u>Answer:</u>
<em>There are 10 numbers between 1-100 which are equal to 5 times an odd number.</em>
<u>Explanation:</u>
<em>The odd numbers between 1 and 100 are 1,3,5,7…..
</em>
When these when these odd numbers are multiplied by 5 we get the following result.


<em>These products form an AP 5,15,25,…..,95
</em>
common difference d=10
first term
last term
we have to calculate the number of terms n
The expression for last term
of an AP is
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