Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
Answer:
12.89 moles
Explanation:
Before we solve the question, we have to balance the equation of the reaction first. The balanced reaction will be:
2 NO + 2 H2→ N2 + 2 H2O
There are 180.5g of N2 produced, the number of produced in moles will be: 180.5g / (28g/mol)= 6.446 moles
The coefficient of H2 is two and the coefficient of N2 is one. Mean that we need two moles of H2 for every one mole of N2 produced. The number of H2 reacted will be: 2/1 * 6.446 moles = 12.89 moles
6.3 ×
![10^0](https://tex.z-dn.net/?f=10%5E0)
In scientific notation, the numerical value without the exponent of 10 must be within the range from 1 to just below 10 (for example, 9.99...). In this case, 6.3 is already within this range, so we just have to multiply it by 1. To get a multiplier of 1 using base 10, we would have to raise 10 to the zeroth power.
Given :
Mass of
is 571.6 g per liter .
Density of solution ,
.
To Find :
a. Mass percentage
b. Mole fraction
c. Molality
d. molarity of H2SO4 in this solution.
Solution :
Molar mass of
, m = 1329 g/mol .
a ) Mass of
contain in 1 liter is 1329 g .
![mass \ \%=\dfrac{571.6}{1329}\times 100=43.01 \%](https://tex.z-dn.net/?f=mass%20%5C%20%5C%25%3D%5Cdfrac%7B571.6%7D%7B1329%7D%5Ctimes%20100%3D43.01%20%5C%25)
b ) Moles of
=
.
Moles of
=
.
Mole fraction
.
c ) Molarity of
.
Hence , this is the required solution .