If 2 is subtracted from a number and this difference is tripled, the result is 8 more than the number.?

1 answer:

4 0

$x-\ number\\\\
3(x-2)=x+8\ \ \ | omit\ the\ bracket\\\\
3x-6=x+8\ \ \ | subtract\ x\\\\
2x-6=8\ \ \ \ | add\ 6\\\\
2x=14\ \ \ | divide\ by\ 2\\\\
x=7\\\\
 Number\ is\ 7.$

You might be interested in

MAKE SURE IT IS 100% CORRECT

masha68 [24]

They are vertical angles. They are congruent.

(2x+2)= (3x-52)

Add 52 to the other side.

2x+54=3x

Subtract 2x on both sides.

54=x

I hope this helps!
~kaikers

7 0

3 years ago

Please help with this question!!

xxMikexx [17]

$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\\\\l\perp k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have the points J(-24, -4) and K(-4, 6)}.\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{substitute:}\\\\m_1=\dfrac{6-(-4)}{-4-(-24)}=\dfrac{10}{20}=\dfrac{1}{2}\\\\\text{therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2\\\\\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{substitute the coordinates of the points J and K:}$

$x=\dfrac{-24+(-4)}{2}=\dfrac{-28}{2}=-14\\\\y=\dfrac{-4+6}{2}=\dfrac{2}{2}=1\\\\\text{midpoint}\ (-14,\ 1)\\\\\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\\text{substitute}\ m=-2,\ x_1=-14\ \text{and}\ y_1=1:\\\\y-1=-2(x-(-14))\\\\\boxed{y-1=-2(x+14)}$