Answer:
probability of an electric power outage shipboard is 0.075 or 7.5 %
Step-by-step explanation:
Given the data in the question;
Probability of engine malfunction = 25% = 0.25
Probability of generator malfunction = 10% = 0.1
Probability of generator being repaired = 50% = 0.5
probability of an electric power outage shipboard = ?
To get the probability of an electric power outage shipboard, we use the expression;
probability of an electric power outage = 2
× p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )
so we substitute in our given values;
probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )
probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75
probability of an electric power outage = 0.075 or 7.5 %
Answer: 2285.71
Step-by-step explanation:
Rearranging the simple interest formula, we have P = A / (1 + rt), where P is the Principal, r is the annaul rate and t is the time period.
r = R/100 = 5%/100 = 0.05 per year.
Solving the equation:
P = 3200 / ( 1 + (0.05 × 8)) = 2285.7142857143
Answer:
It think it is A brainliest?
Step-by-step explanation: