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Usimov [2.4K]
4 years ago
5

What is the area of the black section?

Mathematics
1 answer:
NeX [460]4 years ago
7 0
You can split this up into 3 parts:

The large triangle with base 16cm and height 24.3cm has an area:
A = 1/2bh
A = 0.5x16x24.3
A = 194.4cm²

One of the other triangles with base 13.5cm and height 12cm has an area:
A = 0.5x12x13.5
A = 81cm²

The last triangle with base 13.5cm and height 5cm has an area:
A = 0.5x13.5x5
A = 33.75cm²

So you have 3 triangle areas. To get the black area, you subtract the two white triangles (in your picture) from the area of the large triangle that was first calculated above so:

Black area = 194.4 - 81 - 33.75 = 79.65cm²
That should be the area... I might have messed up on the basic multiplication, but that's the overall process.
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<em><u>Complete Question:</u></em>

The equation a= 180(n-2)/n represents the angle measures, a, in a regular n-sided polygon. When the equation is solved for n, n is equal to a fraction with a denominator of a – 180. What is the numerator of the fraction?

<em><u>Answer:</u></em>

The numerator of fraction is -360

<em><u>Solution:</u></em>

Given that,

<em><u>The equation represents the angle measures, a, in a regular n-sided polygon is:</u></em>

a = \frac{180(n - 2)}{n}

We have to solve the equation for "n"

Rearrange the equation

a \times n = 180(n - 2)\\\\a \times n = 180n - 360\\\\an - 180 n = -360\\\\Take\ n\ as\ common\ factor\\\\n(a-180) = -360\\\\n = \frac{-360}{a - 180}

Thus the numerator of the fraction is -360

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