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3 years ago

What is the area of the black section?

Mathematics

1 answer:

NeX [460]3 years ago

7 0

You can split this up into 3 parts:

The large triangle with base 16cm and height 24.3cm has an area:
A = 1/2bh
A = 0.5x16x24.3
A = 194.4cm²

One of the other triangles with base 13.5cm and height 12cm has an area:
A = 0.5x12x13.5
A = 81cm²

The last triangle with base 13.5cm and height 5cm has an area:
A = 0.5x13.5x5
A = 33.75cm²

So you have 3 triangle areas. To get the black area, you subtract the two white triangles (in your picture) from the area of the large triangle that was first calculated above so:

Black area = 194.4 - 81 - 33.75 = 79.65cm²
That should be the area... I might have messed up on the basic multiplication, but that's the overall process.

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The length of a side of a cube can be determinad

erik [133]

Answer:

4 cm

which is none of the listed answers

Step-by-step explanation:

∛64 = 4

proof:

4x4x4 = 64

7 0

2 years ago

suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.

emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma( $\alpha ,\beta$ )

E(X)= $\alpha \beta$ $\beta$ = $12^{2}/24$ =6 weeks

V(x)= $\alpha \beta ^{2}$ $\alpha$ =24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, $\alpha$ , $\beta$ , False)

P( $12\leq X\leq 24$ )

P( $12/6\leq G\leq 24/6$ )

P( $2\leq G\leq 4$ )

P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

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4 0

1 year ago

Read 2 more answers

You need to put your reindeer, Rudy, Ezekiel, Gloopin, Bloopin, and Prancer, in a single-file line to pull your sleigh. However,

topjm [15]

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times. Similarly Rudy and Bloopin will be together 4!=24 times. So the number of ways they are not together is 120-24-24=72 ways.

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3 years ago

-5, 20, -80, 320, ... is a geometric sequence a. Find the common ratio, b. Write its recursive rule c. Write its explicit rule.W

mario62 [17]

In order to find the common ratio, we just need to divide a term by the term that comes before it.

So using the terms 20 and -5, we have: