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4 years ago

List three space telescopes and describe the type of radiation studied by each

1 answer:

4 0

Gamma Ray telescopes - they study high energy gamma rays that originate from supernovae, neutron stars, etc.. They require the use of a high altitude balloon or a space mission, as gamma rays are absorbed by the atmosphere.

Ultraviolet telescopes - as from the name itself, these telescopes make their observations at ultraviolet wavelengths. These also require a high altitude observation.

X-ray telescopes - measure x-rays. They can only be observed at the high level of the atmosphere or at space, as x-rays can never travel distances through the atmosphere.

Hope this helps.

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sdas [7]

Answer: A

Explanation:

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2 years ago

How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?

tatyana61 [14]

Missing part in the text of the problem:
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
$Q=m C_s \Delta T$
where
m=1.8 g is the mass of the water
$C_s = 4.18 J/(g K)$ is the specific heat capacity of the water
$\Delta T=2.5 K$ is the increase in temperature.

Substituting the data, we find
$Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E$

We know that each photon carries an energy of
$E_1 = hf$
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz$

So, the energy of a single photon of this frequency is
$E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J$

and the number of photons needed is the total energy needed divided by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons$

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3 years ago

What is the name of the database that Tim Berners Lee built??

dezoksy [38]

Answer:

ENQUIRE is the answer

Explanation: google....internet browser-.. .-.

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3 years ago

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Leya [2.2K]

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3 years ago

Which has a greater buoyant force on it, a 25.0 cm3 piece of wood floating with part of its volume above water or a 25.0 cm3 pie

kozerog [31]

Answer:

piece of submerged iron

Explanation:

The buoyant force is given by:

$B=\rho_L V_{sub} g$

where

$\rho_L$ is the density of the liquid (in this case, water)

$V_{sub}$ is the submerged part of the object

g is the acceleration due to gravity

In this problem, the liquid used in the two examples is the same, water, so $\rho_L$ is the same; and g is the same as well. Therefore, the only difference between the two examples is $V_{sub}$ .

For the piece of wood, we are told that the object is floating, so only a fraction of its total volume of 25.0 cm3 will be submerged: therefore the submerged volume will be less than 25.0 cm3. On the contrary, the problem tells us that the piece of iron is submerged, so the submerged volume in this case is 25.0 cm3. Therefore, the submerged volume for the iron is greater than for the piece of wood, so the buoyant force of the piece of iron is greater.

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3 years ago