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Ludmilka [50]
3 years ago
10

Knowing who writes the source is an important as long as the information is correct?

Physics
1 answer:
monitta3 years ago
6 0

That isn't correct. You need to be able to cite everything. wHO WRITE IT WHAT WAS SAID WHAT YEAR...


Sorry for all caps.

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Machines
Ainat [17]

Explanation:

Hey there!!

Here, Given is,

Efficiency = 75%

VR = no. of pulleys = 5

Now,

effeciency =  (\frac{ma}{vr} ) \times 100\%

75\% =  \frac{ma}{5}  \times 100\%

100% ma = 75%×5

ma =  \frac{75\% \times5}{100\%}

ma =  \frac{375\%}{100\%}

Therefore, MA is 3.75.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
Read 2 more answers
An instrument used to detect a static electric charge is called an
Eddi Din [679]
It is B. false that an instrument used to detect a static electric charge is called an ammeter. It is actually called an electroscope. Ammeter measures current. 
7 0
3 years ago
Read 2 more answers
A(n) ____ is a material that takes in a wave when the wave hits it.
Whitepunk [10]

The correct answer is:

Absorber

An absorber is a material that takes in a wave when the wave hits it.

|Huntrw6|

5 0
4 years ago
Read 2 more answers
A baseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the p
satela [25.4K]
The work done by the friction force to stop the player is equal to his loss of kinetic energy:
W= \Delta K

The work done by the friction force is the magnitude of the force \mu m g times the distance covered by the player, d:
W= \mu mg d

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
\Delta K=K_i =  \frac{1}{2}mv^2

Substituting into the first equation, we get:
\mu m g d=  \frac{1}{2}mv^2
from which we find d, the distance covered by the player:
d= \frac{v^2}{2 \mu g}= \frac{(4.0 m/s)^2}{2 \cdot 0.4 \cdot 9.81 m/s^2}=2.04 m
4 0
3 years ago
A light source simultaneously emits light of two wavelengths, 480 nm and 560 nm, respectively. The source is used in a double-sl
Assoli18 [71]

Answer:

0.48 cm

Explanation:

given data

wavelength = 480 nm

wavelength = 560 nm

slit spacing = 0.040 mm

distance between double slits and the screen  = 1.2 m

solution

we know that  (1 nm= 10^{-9} m)

we wil take here equation of equations of interference that is

ym = R × (m λ)/d    ..........................1

here m = 2 R  i.e distance of screen and slit

 so put here value and we get

separation between the second-order bright fringes = 0.48 cm

6 0
4 years ago
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