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djverab [1.8K]
4 years ago
10

A major artery with a cross sectional area of 1.00cm^2 branches into 18 smaller arteries, each with an average cross sectional a

rea of 0.400cm^2. By what factor is the average velocity of the blood reduced when it passes into these branches
Physics
1 answer:
dybincka [34]4 years ago
3 0

Here we can say that rate of flow must be constant

so here we will have

A_1v_1 = 18 A_2v_2

now we know that

A_1 = 1 cm^2

A_2 = 0.4 cm^2

now from above equation

1 cm^2 v_1 = 18(0.400 cm^2)v_2

\frac{v_2}{v_1} = \frac{1}{18\times 0.4}

\frac{v_2}{v_1} = 0.14

so velocity will reduce by factor 0.14

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Two sound waves, from two different sources with the same frequency of 420 Hz travel in the same direction at 336 m/s. The sourc
Tresset [83]

Answer:

Pi(3.14) radians or 180º degrees

Explanation:

First of all, we need to obtain the wavelength of a wave traveling to the speed of sound and 420 Hz of frequency.

The formula is:

l=wavevelocity/frequency

where l = wavelength in meters

With current values:

l = 336 [m/s]/420[1/s] = 0.8 meters

Since a complete cycle (360º or 2pi radians) needs 0.8 meters to complete, 0.4 meters or 40 cm is just half of it, making a 180º degree phase or 3.14 radians.

8 0
3 years ago
The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bezzdna [24]

Answer:

4589.05 year

Explanation:

The relation of activity is given by A=A_0e^{\lambda t} we have given \frac{A}{A_0}=0.574

Half life T=5730\ years

We know that half life T=\frac{0.693}{\lambda }

\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year

So 0.574=e^{-1.2094\times 10^{-4}t}

e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742

{1.2094\times 10^{-4}t}=ln1.742=0.555

t=\frac{0.555}{1.2094\times 10_{-4}}=4589.05\ year

7 0
3 years ago
If 4000 C of charge pass through a section of wire in 50 seconds, what would the current be?
9966 [12]

Answer:

Explanation:

Given that,

Charge through a wire is

Q = 4000C

Time for charge to pass through the wire is

t = 50seconds

Then,

Current through the wire is the rate of charge passing through the wire

Q = it

Where

Q is charge.

I is current

t is time taken

Therefore,

I = Q / t

I = 4000 / 50

I = 80 Amps

3 0
4 years ago
An object has a mass of 8.00 kg. what is the gravitational force of the object on earth
KonstantinChe [14]

When a mass of 8 kg is located on the Earth's surface, the magnitude of each of
the gravitational forces attracting the mass and the Earth toward each other is

       (mass) x (acceleration of gravity on Earth) =

      (8.0 kg) x (9.81 m/s²) =

                78.48 kg-m/s²  =  <em>78.48 newtons  </em>(about 17 pounds 10.2 ounces)


6 0
4 years ago
Read 2 more answers
An automobile with tires that have a radius of 0.260 m travels 76000 km before wearing them out. How many revolutions do the tir
Tomtit [17]

Answer:

Explanation:

circumference of the tyre = 2πr = 2 x 3.14 x 0.26 = 1.6328m

76000km = 76000000m

no of revolutions required

= 76000000/1.6328 = 46546 revolutions.

3 0
3 years ago
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