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kolbaska11 [484]
3 years ago
5

A boy throws a rock with an initial horizontal velocity of 17.0 m/s and an initial vertical velocity of 21.0 m/s. How high above

the boy's hand is the rock after 2.8 s?
Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

53.2

Explanation:

You can use the kinematic equation: displacement of x = (initial velocity + final velocity)*t/2

Subsititing: 17+21 = 38 * 2.8/2 = 53.2

Note: Displacement = distance between the 2 points

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(b) Figure 3 shows a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three
sleet_krkn [62]

An equation showing the relationship between the THREE forces is R -W +F= 0

<h3>What is moment of force?</h3>

The equal and opposite force acting at a point from the axis of rotation is called the moment of force.

M = F x r

Given is a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three forces acting on it

Taking moment about the wheel, we get

-43x 9.81 x 0.6 + F x 1.5 =0

F = 43 x 0.6/1.5

F = 168.732 N (upward force)

Summation of forces in y direction is zero.

R -W +F= 0

Where, R is the normal force, W is the Weight force and F is the applied force.

Thus, this is the equation representing all the three forces acting on wheelbarrow.

Learn more about moment of force.

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3 0
2 years ago
In what form is carbon found in the atmosphere?
svlad2 [7]

Answer:

Carbon is found in the atmosphere mostly as carbon dioxide.

Explanation:

4 0
3 years ago
A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the c
icang [17]

Answer:

a. 900 J

b. 0.383

Explanation:

According to the question, the given data is as follows

Horizontal force = 150 N

Packing crate = 40.0 kg

Distance = 6.00 m

Based on the above information

a. The work done by the 150-N force is

W = F x = \mu N x = \mu\ m\ g\ x

W = 150 \times 6

= 900 J

b. Now the coefficient of kinetic friction between the crate and surface is

\mu = \frac {F}{m\timesg}

= \frac{150}{40\times 9.8}

= .383

We simply applied the above formulas so that each one part could calculate

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Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.
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B. have eight electrons in their outer shell
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3 years ago
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