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diamong [38]
3 years ago
13

Write out the rule and fill in the empty boxes. Complete the function table.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

Rule: Input ÷ -8 = Output

Output Blanks: -45, -28, -39, - 43 (top to bottom)

Step-by-step explanation:

Let's start by finding the rule using the 2 given outputs.

Think about it like this. What do we have to do to 360 (the input) to get -45 (the output)?

We can see that the input is larger that the output, so start with division

360/x = -45

Multiply both sides of the equation by 1x

360 = -45x

Divide both sides of the equation by -45

x = -8

We now know that the rule is:

Input ÷ -8 = Output

-------------------------------------------------------------------------------------------------

Now that we have the rule, let's complete the function table.

224 (input).

224/-8 = -28

The output is -28

312 (input)

312/-8 = -39

The output is -39

See the attached image for the completed table with the values above.

Let me know if you have any questions!

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Answer:

The amount of pages that remain to be read is <u>150 pages</u>

Step-by-step explanation:

Okay if we know it's in 7:3 ratio we can easily add them both to get 10, then divide 10 by 500 to get 50. SO we now know that 50 is 1 unit and since the ratio says 3 units is the answer, we multiply 50 by 3 to get 150.

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3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
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