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3 years ago

When large amplitude sound vibrates the ear significantly, a _______ results.

Physics

2 answers:

Zanzabum3 years ago

8 0

I believe that the answer is D. loud sound.

inysia [295]3 years ago

4 0

Its B since the loudness is determend of the volume and sound. Also, if its loud, it cant be low or soft, so that sum's it up to B

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Answer:

Unemployment cause stress which ultimately has long-term physiological health effect

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3 years ago

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Answer:

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3 years ago

The ground state electron configuration of an al atom is.

RUDIKE [14]

Answer:

A neutral atom of aluminum has 13 protons and 13 electrons. The ground state electron configuration for aluminum is 1s22s22p63s23p1. A shorthand way to write the electron configuration, called noble gas notation, is [Ne]323p1.

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3 years ago

A. Una onda armónica que se propaga por un medio unidimensional tiene una frecuencia de 500Hz y una velocidad de propagación de

Natasha2012 [34]

Answer:

0.117 m

Explanation:

First of all, we can find the wavelength of the wave in the problem, by using the wave equation:

$v=f\lambda$

where:

v = 350 m/s is the speed of the wave

f = 500 Hz is the frequency of the wave

$\lambda$ is the wavelength

Solving for $\lambda$ ,

$\lambda=\frac{v}{f}=\frac{350}{500}=0.7 m$

This means that the distance between two consecutive points of the wave having a difference of phase of

$\phi=2\pi$

is 0.7 m.

Here we want to find the distance between two points that have a difference of phase of

$\phi'=\frac{\pi}{3}$

So, we can set up the following rule of three:

$\frac{d}{\phi}=\frac{d'}{\phi'}$

where d' is the distance we are looking for. Solving for d',

$d'=d\frac{\phi'}{\phi}=(0.7)\frac{\pi/3}{2\pi}=\frac{1}{6}(0.7)=0.117 m$

7 0

3 years ago

A transformer with 1000 turns on the primary coil is used to decrease the voltage from 2500 V to 120 V for home use. How many tu

Katyanochek1 [597]

Answer:

The number of turns in the secondary coil is 48.

(B) is correct option.

Explanation:

Given that,

Number of turns on primary coil= 1000

Primary voltage = 2500 V

Secondary voltage = 120 v

We need to calculate the turns in the secondary coil

Using relation between voltage and number of turns in primary and secondary coil

$\dfrac{V_{s}}{V_{p}}=\dfrac{N_{s}}{N_{p}}$

Put the value into the formula

$\dfrac{120}{2500}=\dfrac{N_{s}}{1000}$

$N_{s}=\dfrac{120}{2500}\times1000$

$N_{s}=48\ turns$

Hence, The number of turns in the secondary coil is 48.

5 0

4 years ago