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3 years ago

Which type of experiment involves changing only one variable at a time

Physics

2 answers:

BlackZzzverrR [31]3 years ago

6 0

Controlled Experiment

muminat3 years ago

3 0

Answer:

Controlled experiment

Explanation:

the correct answer is Controlled experiment

To test certain variable scientist sometimes manipulate the experiment by allowing change of only one variable at one time this experiment is known as a controlled experiment.

A controlled experiment is done in an experiment to get to see the effect on the specimen by changing the variables.

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Changes in the forms of energy are called

Dima020 [189]

<span>Changes in the forms of energy are called "Energy Conversions"

Hope this helps!</span>

5 0

3 years ago

The 5-lb collar is released from rest at A and travels along the frictionless guide. Determine the speed of the collar when it s

Sholpan [36]

Answer:

Explanation:

Stiffness of spring k equal to 4 lb/ft.

Unstretched length of the spring L is equal to 0.5 feet.

Weight of the collar W is 15lb

Radius of curvature of curve guide is 1 feet

length of vertical rod is 1.5 feet

Initial speed of collar when released from rest at A is 0 feet per seconds

use the energy conservation equation

$P_A +K_A=P_B+K_B$

Estimate the potential energy , component as position B as below

$P_A=Wh_1+\frac{1}{2} ks^2_1\\\\=5\times(1.5+1)+\frac{1}{2} \times 4 \times(1.5+1-0.5)^2\\\\=20.5lb.ft$

Estimate the kinetic energy , component as position A as below

$K_A=\frac{1}{2} \frac{W}{g} V^2_1\\\\=\frac{1}{2} \frac{5}{32.2} \times0^2\\\\=0lb.ft$

Estimate the kinetic energy , component as position B as below

$K_A=\frac{1}{2} \frac{W}{g} V^2_2\\\\=\frac{1}{2} \frac{5}{32.2} \times V^2_2\\\\=00777V^2_2$

Substitute 20.5lb- ft for $P_A$

0.5lb-ft for $P_B$

0lb -ft for $K_A$

$0.0777V_2^2 for K_B$

$20.5+0=0.5+0.777V^2_2\\\\V^2_2=257.6\\\\V_2=16.05$

= 16.05ft/sec

7 0

3 years ago

If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a fun

inessss [21]

Answer:

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

$s=-8t^2+32t$ ...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

$\dfrac{ds}{dt}=0$

$\dfrac{d(-8t^2+32t)}{dt}=0$

-16 t + 32 = 0

t = 2 seconds

Put the value of t in equation (1) as :

$s=-8(2)^2+32(2)$

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

6 0

4 years ago

Which term describes the number of troughs that pass a point in a given amount of time?

artcher [175]

Answer:

Frequency (f) can be defined as the number of waves or crests or number of troughs that pass a point per unit second. It can be measured in Hertz (Hz) or 1/s.

6 0

3 years ago

A rocket with a mass of 2.0 Ã 106 kg is designed to take off from the surface of the earth by burning fuel and ejecting it with

julsineya [31]

thrust force getting from the burning of mass should balance the weight of the rocket

here thrust force is given as

$F_t = v\frac{dm}{dt}$