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Ne4ueva [31]
3 years ago
12

A 52.0 kg skateboarder does a trick on a half-pipe. During the trick, he reaches a speed of 8.90 m/s. The radius of the half-pip

e ramp is 3.00 meters. What is the minimum centripetal force necessary to keep the skater on the ramp?
Physics
1 answer:
Lyrx [107]3 years ago
3 0
A= (8.9)^2/3=26.4
f=26.4*52=1372.97N
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