2 years ago

A person just supports a mass of 20kg suspended from a rope.

Physics

1 answer:

Georgia [21]2 years ago

7 0

Answer:

F = 200 N

Explanation:

Given that,

The mass suspended from the rope, m = 20 kg

We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,

F = mg

Where

g is acceleration due to gravity

Put all the values,

F = 20 kg × 10 m/s²

F = 200 N

So, the resultant force on the mass is 200 N.

You might be interested in

A pendulum is formed by taking a 2kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. It is ob

Mekhanik [1.2K]

Please elaborate more on your question so I can help you

5 0

3 years ago

A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force act

MA_775_DIABLO [31]

Answer:

cos 0 = 1.

Fs = 7×8 = 56 J

Explanation:

7 0

3 years ago

Which of the following describes the way heat is transferred in a geyser?

Iteru [2.4K]

Answer:

Heat is transferred by the hot air or water moving to a cooler area. The elements rotate in circular motions, giving the geyser pressure.

5 0

3 years ago

With the piston head locked in place, will the volume of the gas increase, decrease, or stay the same whenthe piston is placed a

Nuetrik [128]

Answer:

For real gas the volume of a given mass of gas will increase with increase in temperature.

Explanation:

With the piston head locked in place and place above the fire,the volume of the gas will increase,because the volume of a given mass of gas increases with increase temperature.

6 0

3 years ago

An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o

Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

$v_y = 0$

While the horizontal velocity is

$v_x = 15 m/s$

The horizontal distance covered is

$d_x = 2.7 m$

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

$t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s$

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

$d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m$

8 0

3 years ago