They are alike because you are just doubling the number by 2
Solve by substitution
Just plug in y=-x-1 into y+x=3
So we get:
Simplify that:
And since that is not true, that means this system of equations has no solutions!
Answer:
16
Step-by-step explanation:
You see, if you were to plot these points, (1, 2) and (1, 7) would be 5 points away from each other. If you were to plot the points (4, 2) and (4, 7) those points would also be 5 points away from each other. Now, (1, 2) and (4, 2) are 3 points apart as well as (1, 7) and (4, 7). Therefore, 5 + 5 = 10, 3 + 3 = 6, and finally, 10 + 6 = 16!
A.Fractions and decimals are not integers<span>. All whole </span>numbers<span> are</span>integers<span> (and all natural </span>numbers<span> are </span>integers<span>), but not all </span>integers<span>are whole </span>numbers<span> or natural </span>numbers<span>. For example, -5 is an </span>integer<span>but not a whole </span>number<span> or a natural </span>number<span>.
B.</span><span>A </span>number<span> is </span>rational<span> if it can be represented as p q with p , q ∈ Z and q ≠ </span>0<span> . Any </span>number<span> which doesn't fulfill the above conditions is irrational. It can be represented as a ratio of two integers as well as ratio of itself and an irrational </span>number<span> such that </span>zero<span> is not dividend in any case
</span>C.<span>In mathematics, an </span>irrational number<span> is any </span>real number<span> that cannot be expressed as a ratio of integers. </span>Irrational numbers<span> cannot be represented as terminating or repeating decimals.
</span>D.<span>The correct answer is </span>rational<span> and </span>real numbers<span>, because all </span>rational numbers<span> are also </span>real<span>. Correct. The </span>number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational.
</span> Witch one do u think it is??
If f(x) is an anti-derivative of g(x), then g(x) is the derivative of f(x). Similarly, if g(x) is the anti-derivative of h(x), then h(x) must be the derivative of g(x). Therefore, h(x) must be the second derivative of f(x); this is the same as choice A.
I hope this helps.
