Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
look the photo
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Answer:
3325/5=665
Step-by-step explanation:
Answer:
2a=1/2
a=1/4
Step-by-step explanation:
Subtract 33 from both sides
6x>3x+30-36x>3x+30−3
Simplify 3x+30-33x+30−3 to 3x+273x+27
6x>3x+276x>3x+27
Subtract 3x3x from both sides
6x-3x>276x−3x>27
Simplify 6x-3x6x−3x to 3x3x
3x>273x>27
Divide both sides by 3
3x>\frac{27}{3}x>
3x> 27
Simplify \frac{27}{3}
3
ANSWER: x>9