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Dafna11 [192]
2 years ago
15

type of weapon of mass decruction taht spreads deadly radioactive material by way of conventinal explosion

Computers and Technology
1 answer:
sashaice [31]2 years ago
6 0
Nuclear bombs would be my best answer
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When you open a browser window, it open in a _____. <br> a. fieldb. folderc. menud. window?
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D. A window the rest are incorrect
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3 years ago
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

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The Save command saves your changes silently without additional prompts, using the same save settings; the Save As command reope
kirza4 [7]

The "Save command" saves your changes <u>silently</u> without additional prompts and it uses the same save settings while the "Save As command" <u>reopens</u> the Save screen: True.

What is the Save command?

A Save command can be defined as a type of command associated with the file menu of a software application and it causes a copy of the current file to be created and stored to a specific location on a computer system.

<h3>What is the Save as command?</h3>

A Save command can be defined as a type of command associated with the file menu of a software application and it causes a copy of the current file to be created and stored to a different location, file name, and/or file type.

In conclusion, the "Save command" saves your changes <u>silently</u> without additional prompts and it uses the same save settings while the "Save As command" <u>reopens</u> the Save screen, so as to enable you make different choices.

Read more on Save command here: brainly.com/question/16852455

5 0
2 years ago
I need help solving this problem on Picoctf. The question is What happens if you have a small exponent? There is a twist though,
soldi70 [24.7K]

Explanation:

Explanation:

RSA encryption is performed by calculating C=M^e(mod n).

However, if n is much larger than e (as is the case here), and if the message is not too long (i.e. small M), then M^e(mod n) == M^e and therefore M can be found by calculating the e-th root of C.

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