All categories

3 years ago

A cardboard of size 16cm and 24cm has been completely used to from a cube.What will be the size of the cube so formed ?

1 answer:

6 0

Surface area of rectangle = l * w = 16 * 24 = 384

Now, Surface area won't change, when it will transform into a cube so,
6a² = 384
a² = 384/6
a² = 64
a = √64
a = 8

In short, Your Answer would be: 8 cm

Hope this helps!

You might be interested in

Factor this expression. You will need to show your work for full credit. b^2-6b+8

Ostrovityanka [42]

B^2-6b+8 turns into b^2-2b-4b+8 due to the sum product pattern. which then turns into b(b-2) - 4(b-2) and then its (b-4)(b-2)

4 0

2 years ago

Diego has some money in his bank account before he starts a summer job. He deposits

Leto [7]

Answer:

he earns $7 per hour

Step-by-step explanation:

6 0

2 years ago

kevin has $42 and is saving $8 per week. how many weeks must kevin save in order to have 138 altogether

Elden [556K]

Answer:

1 year and 5 months

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What are the solutions to the equation (x+5)2=32 ?

Vsevolod [243]

Answer:

x = 11

Step-by-step explanation:

(x+5)2 = 32

2x + 10 = 32

2x = 32 - 10

2x = 22

x = 11

8 0

2 years ago

Read 2 more answers

The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (

sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

$\dfrac{dr}{dt} = 1\text{ meter per hour}$

The height is decreasing at a rate 4 meter per hour

$\dfrac{dh}{dt} = -4\text{ meter per hour}$

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

$\pi r^2 h$

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

$\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}$

Putting all the values we get,

$\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8$

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.

3 0

3 years ago