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3 years ago

A cardboard of size 16cm and 24cm has been completely used to from a cube.What will be the size of the cube so formed ?

1 answer:

6 0

Surface area of rectangle = l * w = 16 * 24 = 384

Now, Surface area won't change, when it will transform into a cube so,
6a² = 384
a² = 384/6
a² = 64
a = √64
a = 8

In short, Your Answer would be: 8 cm

Hope this helps!

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Find the balance in an account at the end of 8 years if $6000 is invested at an interest rate of 4.2% that is compounded continu

tester [92]

Answer:

$8016.00

Step-by-step explanation:

I = 6000 × 0.042 × 8 = 2016

I = $ 2,016.00

$2,016.00 + $6,000.00 = 8,016.00

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3 years ago

The perimeter of a rectangle is 54 feet. The area of the rectangle is 176 square feet. Find the dimensions of the rectangle.

Murrr4er [49]

11 by 16

Explanation:

Set up two equations

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putting this value into the second equation gives.

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multiplying across the parenthesis gives

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subtracting 176 from both sides gives

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176

multiplying by negative one gives

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2 years ago

Suppose a normally distributed set of data with 4800 observations has a mean of 195 and a standard deviation of 12. Use the 68-9

Artemon [7]

Answer:

The number of observations in the data set expected to be below a value of 231 is of 4793.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 195

Standard deviation = 12

The normal distribution is symmetric, which means that 50% of the observations are above the mean and 50% are below.

Proportion of observations below 231:

231 = 195 + 3*12

So 231 is three standard deviations above the mean.

Of the 50% of observations below the mean, all are below 231.

Of the 50% of observations above the mean, 99.7% are between the mean of 195 and three standard deviations above the mean(231).

So, the proportion of observations below 231 is:

$P = 0.5*1 + 0.5*0.997 = 0.9985$

Out of 4800:

0.9985*4800 = 4793

The number of observations in the data set expected to be below a value of 231 is of 4793.

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3 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

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3 years ago

A student is working a part time job delivering pizzas The student earns $40 a shift and earns $1.25 per pizza delivered. One sh

baherus [9]

Answer:

hope this helped

4 0

3 years ago

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