9k2-12k+4
(k2-6k)+(-6k+4) factor out the 3k from 9k2 0 6k: 3k(k-2) factor out -2 from -6k +4n: -2 (3k-2) factor out common term (3k-2) = (3k-2 ) (3k-2) that equals (3k-2)2
14 x 12 = 168
168 divded by 2.90 = 57.9
How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k
so the answer is: 7+28k
i hope i have been helpful :)
Answer:
The answer is below⬇️⬇️
Step-by-step explanation:
f(x) = 3x+4
g(x) = 2x
h(x) = x²+x-2
g(hx) = 2(x²+x-2)
= 2x²+2x-4
f(g(hx))=3(2x²+2x-4)+4
=6x²+6x-12+4
=6x²+6x-8
g(f(g(hx)))=2(6x²+6x-8)
=12x²+12x-16
f(g(f(g(hx))))=3(12x²+12x-16)+4
=36x²+36x-48+4
=36x²+36x-44
h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2
=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46
=1296x⁴+2592x³-1836x²-3132x+1890
f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4
=3888x⁴+7776x³-5508x²-9396x+5674
h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2
=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276
Answer:
x^6y^3
Step-by-step explanation:
<u>Given polynomial:</u>
<u>Get prime factors:</u>
- 2*2*2*x*x*x*x*x*x*y*y*y*y*y - 3*x*x*x*x*x*x*x*x*y*y*y
<u>Common factors of the two terms:</u>
- x*x*x*x*x*x*y*y*y = x^6y^3
<u>So</u>
x^6y^3 is the GCF of this polynomial
