Question

Can someone plz help me with Algebra 2....... :) Will give Brainliest!!

Answer 1

Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
$log((x+6)*(x-6))=2$
so you can simply say that;
$log_{8}((x+6)( x-6))=2$
and by multiplying (x+6)*(x-6)
$log_{8}(x^2-36)=2$
and as you know also that;
$a^{b}=c$ is same as $log _{a}c=b$
so you can simply state it as;
$8^2=x^2-36 64=x^2-36 64+36=x^2 x^2=100 x=10$
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!