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Wittaler [7]
3 years ago
6

Can someone plz help me with Algebra 2....... :) Will give Brainliest!!

Mathematics
1 answer:
Anarel [89]3 years ago
6 0
Using logarithms property of log(x)+log(y)=log(xy)
so here, you can sum the equation to;
log((x+6)*(x-6))=2
so you can simply say that;
log_{8}((x+6)( x-6))=2
and by multiplying (x+6)*(x-6)
log_{8}(x^2-36)=2
and as you know also that;
a^{b}=c is same as log _{a}c=b
so you can simply state it as;
8^2=x^2-36
64=x^2-36
64+36=x^2
x^2=100
x=10
And you can check your work by substituting with 10 instead of x in the original function.
Hope this helps!
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A student sorted 950 crayons into boxes that hold 36 crayons each. How many more crayons will the student need to completely fil
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Anja simplified the expression StartFraction 10 x Superscript negative 5 Baseline Over Negative 5 x Superscript 10 Baseline EndF
Gwar [14]

The mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

<h3>What are coefficients?</h3>

Constants who are in multiplication with variables are called coefficients of those variables.

For example, in 10x^2 we have 10 as coefficient of x^2

Those variables who have got no visible coefficient has 1 as their coefficient. Thus, x^2 has got its coefficient as 1. It is true since 1 multiplied with any number is that number itself.( x^2 = 1 \times x^2 )

<h3>What are some basic properties of exponentiation?</h3>

If we have a^b then 'a' is called base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\\\ a^b \times a^c = a^{b+c} \\\\^n\sqrt{a} = a^{1/n} \\\\(ab)^c = a^c \times b^c

For the considered situation, the expression that Anja is simplifying is:
\dfrac{10x^{-5}}{-5x^{10}}

Anja simplified it to \dfrac{15}{x^{15}}

She performed operations with variable 'x' correctly since

\dfrac{x^{-5}}{x^{10}} = \dfrac{1}{x^5} \times \dfrac{1}{x^{10}} = \dfrac{1}{x^{15}}

But coefficients will also get divided. Instead of dividing 10 by -5, she subtracted them (as 10 - (-5) = 10 + 5 = 15)

This was her mistake.

The correct simplification would be: \dfrac{10x^{-5}}{-5x^{10}} = \dfrac{10}{-5} \times \dfrac{x^{-5}}{x^{10}} = -2 \times \dfrac{1}{x^{15}} = \dfrac{-2}{x^{15}} = -2x^{-15}

Thus, the mistake that Anja made during the simplification of the considered expression is given by: Option C:  She subtracted the coefficients instead of dividing them

Learn more about exponent and bases here:

brainly.com/question/847241

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