Pretty much take that answer and multiply it by 5.
The reason you multiply it by 5 is because a circle can fit 6 equilateral triangles. The smaller section is one of those equilateral triangles so 5 minus 1 is 6. I hope all of this makes sense.
Area of circle = πr² = 64π The cord will subtend a semicircle of diameter 8", radius 4". The area of this semicircle: 1/2 πr² = 0.5 x 4² x π = 8π Area of larger region = area of circle - area of semicircle = 64π - 8π = 56π inch²