Answer:
There are 171 members in the club
Number of boys = 38
Number of girls = 133
Step-by-step explanation:
Let
x = total members of the club
Boys = 2/9x
if there are 95 more girls than boys
Girls = 2/9x + 95
how many girls are there in club?
Total members in the club = boys + girls
x = 2/9x + 2/9x + 95
x = 2+2/9x + 95
x = 4/9x + 95
x - 4/9x = 95
9x-4x/9 = 95
5/9x = 95
Divide both sides by 5/9
x = 95 ÷ 5/9
= 95 × 9/5
= 855/5
= 171
boys = 2/9x
= 2/9 * 171
= 342 / 9
= 38
Girls = 2/9x + 95
= 38 + 95
= 133
Total = 38 + 133
= 171
There are 171 members in the club
Number of boys = 38
Number of girls = 133
If we were to foil
after experieence
we know
ax²+bx+c=0
and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are
b=(bc+ad)
so
in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9
b=9
or you could just expand it
Answer:
4√5
Step-by-step explanation:
Use Pythagorean theorem
a^2=21^2-19^2
a^2=441-19^2
a^2=441-361
a^2=80
a= √80
simplify
Here there are 20 members in all.
Each member paid $2.60.
Total amount paid by members = 20 × 2.60 = $52
The club paid $47.50 to hire the hall. ......Answer
Hence the amount received by the hall = 52 - 4.50 = $ 47.50
The Hall charged $47.50 as the fee.
