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inysia [295]
3 years ago
10

The question is in the picture

Mathematics
1 answer:
GrogVix [38]3 years ago
8 0

Ten-thousand   AFAFANDIUAHDIUAHIUDHAIDh (had to write 20 more "letters")


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You are planning your week-end schedule. You can spend at most 8 hours playing video games and doing homework. You want to spend
MatroZZZ [7]

The system of inequalities is:

v + h ≤ 8

v < 2

h ≥ 1.5

<h3>Which system of equations represents this situation?</h3>

Let's define the variables:

  • v = number of hours playing video games.
  • h = number of hours spent on homework.

The maximum time that you can spend on both activities is 8 hours, then:

v + h ≤ 8

You want to spend less than 2 hours on video games, so:

v < 2

You want to spend at least, 1.5 hours on homework, so:

h ≥ 1.5

Then the system of inequalities is:

v + h ≤ 8

v < 2

h ≥ 1.5

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

7 0
1 year ago
Algebra 1 Assignment! Help needed as soon as possible! thanks so much to whoever helps! have a nice day
mezya [45]

Answer:

Step-by-step explanation:

go-kart = Gk

Head sock = Hs   (what?  a sock in the head?  :/ what ?? )

Laser tag = Lt

Eq 1 ) Gk + Hs + Lt = 33

Eq 2) 2Gk + Hs + 0Lt = 48

Eq 3) 2Gk + Hs + 2Lt =64

This is a system of equations  w/ 3 unknowns and 3 equations so we can solve this. :)

subtract Eq 2 from Eq 3

  2Gk +Hs +2Lt =64

-(2Gk +Hs +0Lt =48)

0Gk + 0 Hs +2Lt = 16

Lt =8    

so one Laser tag game is 8 dollars.. good... now use  8 in Eq. 1 and 3 for Lt price

Eq 1a) Gk + Hs +8 =33    simplify

Eq 1b) Gk + Hs = 25

Eq 3a) 2Gk +Hs +2(8) = 64  simplify

Eq3b) 2Gk + Hs =48

subtract Eq 1b from Eq 3b

2Gk + Hs =48

-(Gk + Hs =25)

Gk = 23

so one Gk ride costs 23 dollars and plug this into Eq 1

23 + Hs + 8 = 33

Hs = 2

Question 1  )  Gk = 23  Hs = 2 Lt = 8

solve new systems, same as above but  with the new prices

Eq 1r ) Gk + Hs + Lt = 18

Eq 2r) 2Gk + Hs + 0Lt = 29

Eq 3r) 2Gk + Hs + 2Lt =35

subtracting 2r from 3r we get 2Lt = 6   then Lt =3  for the new price

plug that into 1r and 3r

Eq 1br) Gk + Hs = 15

Eq 3br) 2Gk +Hs = 29

subtract 1br from 3br

 Gk = 14

plug this into 1r

Hs =1

Question 2 ) Gk=14 Hs =1 Lt=3

Question 3)  wants 2 Hs and 2 Lt

w/o coupon the activities cost 2 ( 2+8)  = 20 dollars

but there is no coupon for 2 of each game

so  no, don't buy a coupon.. just play at full price

Hustler side note.. buy two of the 18 coupons and sell the 2 Gk rides to your   teacher for 15 dollars each, still a good deal to guarantee a good grade on your Home Work ..  (30 total)...... and get your games for just 6 dollars... excellent deal for you   :)

8 0
2 years ago
Please explain your answer
Ymorist [56]

Answer:

51

Step-by-step explanation:

11+(-7)^2-9 - original

11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49

60-9 - add both positives 11+49=60

51 - subtract 9 from 60, 60-9=51

7 0
3 years ago
If f(x)=ln(sin(2x)), f''(π/4) is equal to​
Licemer1 [7]

Use the chain rule to compute the second derivative:

f(x)=\ln(\sin(2x))

The first derivative is

f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}

f'(x)=2\cot(2x)

Then the second derivative is

f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'

f''(x)=-4\csc^2(2x)

Then plug in π/4 for <em>x</em> :

f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4

4 0
3 years ago
Which equations have the same value as 3/5 (30x-15)=72 select 3
const2013 [10]

Answer:

x=4.5

Step-by-step explanation:

Given the equation  \frac{3}{5}(30x-15)=72, we simplify as:

\frac{3}{5}(30x-15)=72\\\\18x-9=72

#We further simplify as multiples of 9(divide by 9 to solve for x):

18x-9=72\\\\2x-1=8\\\\2x=9\\\\x=4.5

Hence, from our simplification  the equation has the same value as x=4.5

5 0
3 years ago
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