He will need exactly 24 stickers. To get this number, you must multiply both sides. :)
Answer:
i)W = 2500 / T
ii) W = 500 Tons
iii) grad W(10°) = - 25î
iv) The formulation is not practical
Step-by-step explanation:
i) Write an equation describing the use of coal
As use of coal is inversely proportional to the average monthly temperature
if W is use of coal in tons/per month then
W(t) = k / T where k is a constant of proportionality and T is the average temperature in degrees. We have to determine k from given conditions
k = ?? we know that when T = 25° W = 100 tons the by subtitution
W = k/T 100 = k /25 k = 2500 Tons*degree
Then final equation is:
W = 2500 / T
ii) Find the amount of coal when T = 5 degrees
W = 2500 / 5
W = 500 Tons
iii)
The inverse proportionality implies that W will decrease as T increase.
The vector gradient of W function is:
grad W = DW(t)/dt î
grad W = - 2500/T² î
Wich agrees with the fact that W is decreasing.
And when T = 100°
grad W(10°) = - 2500/ 100 î ⇒ grad W(10°) = - 25î
iv) When T = 0 The quantity of coal tends to infinite and the previous formulation is not practical
Answer:
The largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb
Step-by-step explanation:
Given
μ = Mean = 10.4 lb
σ = Standard deviation = 3 lb
Using a confidence level of 90%,
We'll need to first determine the z value that correspond with bottom 5% of consumption of banana
α = 5%
α = 0.05
So,
zα = z(0.05)
z(0.05) = -1.645 ----- From z table
Let x represent the largest annual per capita consumption of bananas
The relationship between x and z is
x = μ + zσ
By substitution;
x = 10.4 + (-1.645) * 3
x = 10.4 - 4.935
x = 5.465
Hence, the largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb
