Question

ANSWER FAST PLEASE!!!

Answer 1

Answer:

Yes, with 12 feet leftover.

Step-by-step explanation:

For this problem, you will need to find the area of the floor and the area of both sides of the tent. To find the area of the floor, you will simply need to do 6(8) = 48. To find the area of the sides, you will need to use the Pythagorean theorem to find the height of the sides. Simply divide 6 by 2 to find b². So, the formula will be 3²+4² = c². Solve to get c = 5. Now, find the area of the rectangle by using the formula for area. 8(5) = 40. Multiply 40 by 2 because there are two sides. Now add the total area of both sides and the floor to get a total of 128. Now to see if the canvas can cover the area of the tent, do 140 - 128 to get 12. So the answer is yes, with 12 feet leftover.

Work:

Area of the floor:

6(8) = 48

Area of the sides:

A = 8(h)(2)

A = 16(h)

h² = 3² + 4²

h² = 9 + 16

$\sqrt{h^{2} }$ = $\sqrt{25}$

h = 5

A = 8(5)(2)

A = 80

Total area of the tent:

80 + 48 = 128

Total area of the canvas:

14(10) = 140

Answer to the question:

140 - 128 = 12

By the way, sorry for the late answer. I bet this was on a test, right?