I think the spent about an hour and 15 min on running and 45 min on jogging
ANSWER
![f( - 1) = 2](https://tex.z-dn.net/?f=f%28%20-%201%29%20%3D%202)
EXPLANATION
The given function is a piecewise defined function.
![f( - 1)](https://tex.z-dn.net/?f=f%28%20-%201%29)
is the y-value that corresponds to
![x = - 1.](https://tex.z-dn.net/?f=x%20%3D%20-%201.)
To determine that y-value, we need to trace from
![x = - 1](https://tex.z-dn.net/?f=x%20%3D%20-%201)
to where it meets the graph.
We then trace to the y-axis to determine the corresponding y-value as shown in the diagram.
From the graph, we can see that this x-value corresponds to a y-value of
![2](https://tex.z-dn.net/?f=2)
This implies that, when
![x = - 1,y = 2](https://tex.z-dn.net/?f=x%20%3D%20-%201%2Cy%20%3D%202)
Therefore
![f( - 1) = 2](https://tex.z-dn.net/?f=f%28%20-%201%29%20%3D%202)
See graph.
The key features of a quadratic graph that can identified are; x and y intercepts, axis of symmetry and vertex
<h3>Keys features of a quadratic graph</h3>
The key features are the x-intercepts, y-intercepts, axis of symmetry, and the vertex.
If we add units we can move this function upwards, downwards leftwards and rightwards.
- If we add a positive number to the x-variable, then the graph will move to the left.
- If we add a negative number to the x-variable, then the graph will move to the right.
- If we add a positive number to y-variable, then the graph will move upwards.
- If we add a negative number to y-variable, then the graph will move downwards.
Hence, if we compare the rules we use before with linear function, there's no distinction between horizontal and vertical movements, because if we add to x-variable, then y-variable will be also affected.
Learn more about quadratic graphs here:
brainly.com/question/1214333
#SPJ1
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16
(x^2+10x+16)(x+k)=x^3+9x^2+6x-16
x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16
kx^2+10kx+16k=-x^2-10x-16
k(x^2+10x+16)=-x^2-10x-16
k=(-x^2-10x-16)/(x^2+10x+16)
k=-1
so the width is (x-1)