Answer:
![Average\:Rate\:Change=-59.4](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D-59.4)
Step-by-step explanation:
The given function is
.
We want to find the average rate of change of this function from
to
.
This is given by:
![Average\:Rate\:Change=\frac{f(2)-f(0)}{2-0}](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D%5Cfrac%7Bf%282%29-f%280%29%7D%7B2-0%7D)
This implies that;
![Average\:Rate\:Change=\frac{120(0.1)^2-120(0.1)^0}{2-0}](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D%5Cfrac%7B120%280.1%29%5E2-120%280.1%29%5E0%7D%7B2-0%7D)
![Average\:Rate\:Change=\frac{120(0.1)^2-120}{2}](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D%5Cfrac%7B120%280.1%29%5E2-120%7D%7B2%7D)
![Average\:Rate\:Change=\frac{120((0.1)^2-1)}{2}](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D%5Cfrac%7B120%28%280.1%29%5E2-1%29%7D%7B2%7D)
![Average\:Rate\:Change=\frac{60(0.01-1)}{1}](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D%5Cfrac%7B60%280.01-1%29%7D%7B1%7D)
![Average\:Rate\:Change=60(-0.99)](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D60%28-0.99%29)
![Average\:Rate\:Change=-59.4](https://tex.z-dn.net/?f=Average%5C%3ARate%5C%3AChange%3D-59.4)
Answer:
5x + 3
Step-by-step explanation:
Since we can see DC is the median of Triangle ABC
So it breaks the into two equal parts
Given
AD = 2x + 5
BD = 3x - 2
Now
AB = AB + BD
= 2x + 5 + 3x - 2
= 5x + 3
Hope it will help :)❤
Answer:
three halves
Step-by-step explanation:
1/2 * 3 = 3/2 = 1 1/2 = 1.5
Multiple: 1/2 * 3 = 1 · 3/2 · 1 = 3/2
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(3, 2) = 1. In the following intermediate step, it cannot further simplify the fraction result by canceling.
In other words - one half multiplied by three = three halfs.
There is one answer, -24.
While yes, absolute value does indicate both a positive and negative will work, for every x value there will be only one y value associated with it; if there were more, then it would not meet the criteria to be a function.