All categories

2 years ago

What is a rule for the nth term of the sequence 1/2, 1/4, 1/6, 1/8, ...?

Mathematics

2 answers:

rewona [7]2 years ago

4 0

Answer:

1/18

Step-by-step explanation:

the denominator is going up by 2s

pls brainliest

Art [367]2 years ago

3 0

Answer:

1/18

Step-by-step explanation:

You might be interested in

X^2+6X=16 is a quadratic equation what are the solutions?

IgorC [24]

The answer is 2,-8.
But I am not sure. Hope this will help you!

4 0

3 years ago

Read 2 more answers

What is the solution to the equation 3 − 4(2m + 6) + 3m = −16? (put number answers only)

NISA [10]

Answer:

1. -1

2.-4

3. 2

4.10

4 0

2 years ago

Help me plz I really need this thanks I will give a lot of points

Mashcka [7]

Answer:

see the picture below

Step-by-step explanation:

There is 19, 13, 8, 4, 7, 14, 7, 9.

There is 1 number between 0 and 5.

and there's 4 on between 6 to 10.

and so far.

5 0

3 years ago

Read 2 more answers

A car traveled 3⁄4 mile in one minute at constant speed. What was the speed of the car in miles per hour?

Vanyuwa [196]

60 min = 1 hr

3/4 * 60 = mph (miles per hour)

3/4 * 60 = 45

The speed of the car in mph (miles per hour)

will be 45 mph

Answer = 45mph

Thank you for posting your question on Brainly!

We hope we can help you in the future!

As always I hope you have a great day!

8 0

3 years ago

Read 2 more answers

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers