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NNADVOKAT [17]
3 years ago
10

Imagine a population of 100 individuals, with the initial frequencies A1 = 0.7 and A2 = 0.3. If A1 and A2 are selectively neutra

l what is the probability that the A2 allele will drift to fixation?
a. 70%
b. 30%
c. 3%
d. 0
Mathematics
1 answer:
slega [8]3 years ago
5 0

Answer: b. 30%

Step-by-step explanation:

given data:

population size (n) = 100

A1 = 0.7

A2 = 0.3

if A1 and A2 are selectively neutral, the probability that A2 would drift to fixation

= 0.3

= 30%

there is a. 30% chance that A2 would drift towards fixation.

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Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

\frac{4}{3}x+x+x=60

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

\frac{4}{3}(18)+18+18=60

Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

24+18+18=60

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

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