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3 years ago

14) ΔEFG ~ ΔLMN. Find the ratio of ΔEFG to ΔLMN. A) 1:4 B) 1:2 C) 2:1 D) 4:1

Mathematics

2 answers:

Inessa05 [86]3 years ago

6 0

Answer:

I think the answer is 2:1 but i can't be sure because there is no picturewith the corresponding numbers.

Paha777 [63]3 years ago

5 0

The solution is 2:1. To find the scale factor, simplify $\frac{FG}{MN}$ .

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Plz answer rn nmmmm ASAP!!

notka56 [123]

Answer:

Step-by-step explanation:

7 0

2 years ago

Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???

OLga [1]

Answer:

18/5

Step-by-step explanation:

From my understanding, this is 1 whole 2 upon 10

Step 1: Convert mixed fraction into fraction

Multiply whole number by denominator: 1 x 10 = 10

Add numerator: 10 + 2 = 12

Write the result as the numerator and use the same denominator.

12/10

Step 2: Find the total tape used

From my understanding, each student used 12/10 of the tap

So 3 students used: 12/10 x 3 = 18/5

Therefore, the total tape used for three students was 18/5.

7 0

3 years ago

Please help me thank you so much have a great day and also be nice to others and especially yourself

ioda

8 inches because 80/10=8

6 0

2 years ago

Read 2 more answers

Clasifica los siguientes números en los conjuntos numéricos a los que pertenezcan. Si es posible

Natasha_Volkova [10]

<h2>Please write ur question properly</h2>

5 0

2 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago