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anyanavicka [17]
3 years ago
8

Did anybody subscribe to skeppy this is for an assignment to make a chart

Mathematics
2 answers:
masha68 [24]3 years ago
6 0

Answer:

didnt think that this would be a thing, but yes, i am subscribed

faust18 [17]3 years ago
4 0

Answer:

yes. I did subscribe to skeppy. good luck with the chart.

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LOOK AT PIC PLSS TYYYYY
slava [35]

Answer:

2.52 lbs=40.32 oz

Step-by-step explanation:

I used the mass formula and I even searched it.

2.52 lbs=40.32 oz

Hope this helps! :)

7 0
2 years ago
What is the equation of the following graph in vertex form?
Elza [17]
\bf \boxed{y=(x-{{ h}})^2+{{ k}}}\\\\
x=(y-{{ k}})^2+{{ h}}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
\textit{vertex is at 4,-4}\implies 
\begin{cases}
h=4\\
k=-4
\end{cases}\implies y=(x-4)^2+(-4)
\\\\\\
\boxed{y=(x-4)^2-4}
6 0
3 years ago
Read 2 more answers
You operate a gaming website, www.mudbeast.net, where users must pay a small fee to log on. When you charged $4 the demand was 5
sertanlavr [38]
A) Demand function

price (x)          demand (D(x))

4                      540

3.50                  810

D - 540          810 - 540
----------- =  -----------------
x - 4               3.50 - 4

D - 540
----------- = - 540
x - 4

D - 540 = - 540(x - 4)

D = -540x + 2160 + 540

D = 2700 - 540x

D(x) = 2700 - 540x

Revenue function, R(x)

R(x) = price * demand = x * D(x)

R(x) = x* (2700 - 540x) = 2700x - 540x^2

b) Profit, P(x)

profit = revenue - cost

P(x) = R(x) - 30

P(x) = [2700x - 540x^2] - 30

P(x) = 2700x - 540x^2 - 30

Largest possible profit => vertex of the parabola

vertex of 2700x - 540x^2 - 30

When you calculate the vertex you find x = 5 /2

=> P(x) = 3345

Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.




5 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bars(s).
kirza4 [7]

Answer:

(a)23 (b)90 (c)3

Step-by-step explanation:

The equation for the line of best fit for this situation is given as

y=\frac{3}{10}x+8

where x=average temperature in degrees

y=average number of hot dogs she sold,

(a) The expected number of hot dogs sold when the temperature is 50° would be___hot dogs.

When x=50°

y=\frac{3}{10}X50+8=15+8=23

When the temperature is 50°, the expected number of hot dogs sold would be 23.

(b)If the vendor sold 35 hot dogs, the temperature is expected to be ___degrees.  

If y=35

35=\frac{3}{10}x+8\\35-8=\frac{3}{10}x\\27=\frac{3}{10}x

Multiply both sides by 10/3

27 X \frac{10}{3}= \frac{3}{10}x X \frac{10}{3}\\x=90^{0}

If the vendor sold 35 hot dogs, the temperature is expected to be 90 degrees.  

(c) Based on the line of best fit, for every 10-degree increase in temperature, she should sell 3 more hot dogs.

3 0
3 years ago
6=−w8 how can i solve this
Vaselesa [24]
Divide 6 by -8 to get the variable alone!
6/-8 < division< equation
4 0
3 years ago
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