Answer:
1.25.
Step-by-step explanation:
The common ratio r is 1/5 and the first term a1 = (1/5)^(1-1) = 1.
Sum to infinity = a1 / (1 - r)
= 1 / (1 - 1/5)
= 1 / 4/5
= 5/4
= 1.25 (answer)
Answer:
21 students pass
Step-by-step explanation:
Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction
(which is 75% represented as a fraction).

The fraction
can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with
.

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

The denominators cancel out leaving you with a simple equation to simplify.


Finally, divide both sides by four in order to isolate the variable.

X = 21.
Answer:
3. 6.40
Explanation:
The answer is -5
Explanation: Divide 2 to get rid of the top number. It looks like this
-10. 2y
___. ___
2. 2
What this does is remove the two from the Y and sets it by itself. Then you divide the -10, and the answer is -5