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3 years ago

A trail around a river is 3 1/4 miles long. What is the length, in feet, of the trail?

Mathematics

1 answer:

Law Incorporation [45]3 years ago

3 0

5280 feet in a mile
3.25 x 5280 = 17160 feet

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Brandy solved 1/6÷5 by using a related multiplication expression. What multiplication expression did she use?

tekilochka [14]

Answer:

THE ANSWER IS 30

Step-by-step explanation:

We can solve this problem by multiplication expressions. See below.

1/6 ÷5 $= \frac{1}{6} * \frac{1}{5} = \frac{1}{30} =$ 30

8 0

2 years ago

If you borrow $675 for six years at a interest rate of 10% how much interest will you pay

murzikaleks [220]

Answer:

the answer is $40.5

Step-by-step explanation:

the basic formula of finding our interest is I = PxRxT

P (principal) = 675

R (rate) = 10% (we have to turn it into a decimal which is 0.010)

T (time) = 6 years

so :

I = 675 x 0.010 x 6

I = 40.5

7 0

3 years ago

What is 1 1/4 + 3 5/8 = when its reduced to lowest term.

nikdorinn [45]

Answer:

4 7/8 or 4.875

Step-by-step explanation:

1 1/4 + 3 5/8 = 4 7/8 or 4.875

PLEASE MARK ME AS BRAINLIEST UWU

5 0

2 years ago

Read 2 more answers

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde

Lilit [14]

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

Point G is located at (6, 2)

When reflected over the y-axis:

G'(-6,2).

The ordered pair that best describes the location of G' is (-6,2).

5 0

2 years ago