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photoshop1234 [79]
3 years ago
14

A sequence of transformations was applied to an equilateral triangle in a coordinate plane. The transformations used were rotati

ons,reflections, and translations. Which statement about the resulting figure is true?
A) It must be an equilateral triangle with the same side lengths as the original triangle
B) It must be an equilateral triangle, but the side lengths may differ from the original triangle
C) It May be a scalene triangle, and all the side lengths may differ from the original triangle,
D) It May be an obtuse triangle with at least one side the same length as the original triangle
Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

A- It must be an equilateral triangle with the same side lengths as the original triangle

Step-by-step explanation:

Well The Equilateral Triangle dont change at all But its position on the coordinate plane changes, So it must be still a Equilateral Triangle.

The other options are talking about how the equilateral triangle changes, But it not true only the positions on the coordinate plane changes.

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timurjin [86]

The answer is nine .nine is not a perfect square.

8 0
4 years ago
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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
Tema [17]

Step 1) Divide up the figure

In this figure, there is a triangle, a small rectangle, and two larger rectangles. The triangle is 6 in x 9 in, the small rectangle is 3 in x 18 in, one of the large rectangles (center) is 8 in x 14 in, and the other large rectangle (bottom) is 5 in x 9 in.

Step 2) Find the area of each shape in the figure

Triangle: A = 1/2 x 6 x 9 = 27

Small rectangle: A = 3 x 18 = 54

Large rectangle (center): A = 8 x 14 = 112

Large rectangle (bottom): A = 5 x 9 = 45

Step 3) Add the area of each shape together

A = 27 + 54 + 112 + 45 = 238 square inches

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3 years ago
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A single die is rolled twice. The 36​ equally-likely outcomes are shown to the right. Find the probability of getting first an o
dangina [55]
36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)

Solution:
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