Answer:
4/7 yards
Step-by-step explanation:
Given that :
Required fabric is > 1/2 but < 5/8
Let required fabric = x
Then ;
Converting the fractions to decimal :
1/2 = 0.5 ; 5/8 = 0.625
0.5 < x < 0.625
3/8 yards = 0.375 ;
4/7 yards = 0.571
3/7 yards = 0.429
2/4 yards = 0.5
0.5 < 0.571 < 0.625
From the options, only 4/7 yards satisfies the condition :
Answer:
85j-6/5j
Step-by-step explanation:
Answer:
-2948
Step-by-step explanation:
the only fraction it can be is -2948/1 but it is the same thing as the answer itself
We will find the answer using the second law of motion i.e. Force is equal to the product of mass and acceleration.
![\sf \: F=ma](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20F%3Dma)
Where,
- F is force
- M is mass
- A is acceleration
In our case,
Let's solve for M ~
![\tt \: 32 = m \times 0.88](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%2032%20%3D%20m%20%5Ctimes%200.88)
![\tt \: 32 = 0.88m](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%2032%20%3D%200.88m)
![\tt \: 0.88m = 32](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%200.88m%20%3D%2032)
![\tt \: m = 36.36](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20m%20%3D%2036.36)
<em>Thus, The mass of object is 36.36 </em><em>grams</em><em>.</em><em>.</em><em>.</em><em>~</em>