Applying a quadratic regression model y = ax2 + bx + C,

someone help. i can’t seem to figure this out, it’s simple math but i just don’t understand it i need the answer as soon as poss

Gre4nikov [31]

For each of the squares, the area is 32. (6x6, also known as height and width.). There is 3 squares. 32 x 3 =96.

Hope this helps!

5 0

3 years ago

The angles of depression of two ships from the top of the light house are 45° and 30° towards east. If the ships are 200 m apart

azamat

Answer:

273 meters

Step-by-step explanation:

See image attached for the diagram I used to represent this scenario.

The distance between the ships, at angles 30 and 45, is 200 meters. The distance between the left ship and the lighthouse is x meters.

We can use trigonometric ratios to solve this problem. We can use the tangent ratio $\big{(} \frac{\text{opposite}}{\text{adjacent}} \big{)}$ to create an equation with the two angles.

$\displaystyle \text{tan(45)} = \frac{h}{x}$
$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Let's take these two equations and solve for x in both of them.

<h2> $\textbf{Equation I}$ </h2>

$\displaystyle \text{tan(45)} = \frac{h}{x}$

tan(45) = 1, so we can rewrite this equation.

$\displaystyle 1=\frac{h}{x}$

Multiply x to both sides of the equation.

$\displaystyle x = h$

<h2> $\textbf{Equation II}$ </h2>

$\displaystyle \text{tan(30)} = \frac{h}{x+200} }$

Multiply x + 200 to both sides and divide h by tan(30).

$\displaystyle \text{x + 200} = \frac{h}{\text{tan (30)}}$

Subtract 200 from both sides of the equation.

$\displaystyle \text{x} = \frac{h}{\text{tan (30)}} - 200$

Simplify h/tan(30).

$x=\sqrt{3}h - 200$

<h2> $\textbf{Equation I = Equation II}$ </h2>

Take Equation I and Equation II and set them equal to each other.

$h=\sqrt{3}h-200$

Subtract √3 h from both sides of the equation.

$h-\sqrt{3}h=-200$

Factor h from the left side of the equation.

$h(1-\sqrt{3}) =-200$

Divide both sides of the equation by 1 - √3.

$\displaystyle h=\frac{-200}{1-\sqrt{3} }$

Rationalize the denominator by multiplying the numerator and denominator by the conjugate.

$\displaystyle h=\frac{-200}{1-\sqrt{3} } \big{(} \frac{1+\sqrt{3} }{1+\sqrt{3}} \big{)}$
$\displaystyle h=\frac{-200+200\sqrt{3} }{1-3}$
$\displaystyle h =\frac{-200+200\sqrt{3} }{-2}$

Simplify this equation.

$\displaystyle h=100+100\sqrt{3}$
$h=273.20508075$

The height of the lighthouse is about 273 meters.

5 0

3 years ago

Read 2 more answers

Please help tysm if you decide to help c:

erma4kov [3.2K]

Answer:

B

Step-by-step explanation:

Hello :)

The question is asking about true statements, so let's go through the choices.

A) The profit increased for all five months; this question means that the profit (money value) should have increased every month; while it does from June to September, October goes down so this statement is false.

B) This statement is saying June + 100,000 dollars+ =August. June's profit is approximately 150,000 lower than August so this is true.

C) This answer choice explains October's profit was less than June's; 298,000 from October is bigger than 248,000 from June so this is false.

D) I can't read off the last statement but no profit is drastically bigger than the other for it to be twice as much of September.

4 0

2 years ago

annie needs a piece of cardboard with an area of 180 square centimeters. the length of the cardboard should be 7 centimeters les

baherus [9]

The length is 20 and the width is 9. Hope this helps.

8 0

3 years ago

Please answer 12.) quick ! :(

Sonja [21]

Answer:

A: $48.53

B: $58.23

Step-by-step explanation:

7% of 45.36 is 3.17.

20% of 48.53 is 9.70.

correct me if i'm wrong. hope this helps. :)

7 0

2 years ago