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kolbaska11 [484]
3 years ago
9

What is the temperature of 0.55 mol of gas at a pressure of 1.5 atm and a volume of 12.6 L ?

Chemistry
1 answer:
Taya2010 [7]3 years ago
3 0

Answer:

The temperature is 419,1 K

Explanation:

We use the formula PV=nRT  T=PV/nR

T=1,5 atm x 12,6 L/0,55 mol x 0,082 l atm/K mol

T= 419,0687361 K

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Make an observation about the average height of the beanbag for each mass dropped. How does it compare with your calculated kine
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Answer:

the other person is correct

Explanation:

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2 years ago
Calculate the mass of 5.3 moles of chloric acid (hcl03)
Minchanka [31]
If I did the math right .. it would be 84.46grams
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2 years ago
Find the ph of a buffer that consists of 0.18 m ch3nh2 and 0.73 m ch3nh3cl (pkb of ch3nh2 = 3.35)?
ozzi
Hello!

First, we need to determine the pKa of the base. It can be found applying the following equation:

pKa=14-pKb=14-3,35=10,65

Now, we can apply the Henderson-Hasselbach's equation in the following way:

pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04

So, the pH of this buffer solution is 10,04

Have a nice day!
8 0
2 years ago
Titanium dioxide (TiO2) is used extensively as a white pigment. It is produced from an ore that contains ilmenite (FeTiO3) and f
STALIN [3.7K]

Answer:

2928kg of ore are required.

2585kg of the 80% H₂SO₄ solution are required.

Explanation:

To solve this question we need first to find the moles of titanium in 1000kg of TiO₂. Keeping in mind the 89% of descomposition we can find the mass of the ore and the mass of the 80% sulfuric acid required:

<em>Moles TiO₂ -Molar mass: 79.866g/mol-:</em>

1x10⁶g * (1mol / 79.866g) = 12521 moles Titanium

In mass -Molar mass Ti: 47.867g/mol-:

12521 moles Titanium * (47.867g / mol) = 599341.4g of Ti.

As the ore contains 24.3% of Ti:

599341.4g of Ti = 599.34kg Ti * (100 / 24.3) = 2606kg ore

As the descomposition is just of 89%:

2606kg ore * (100 / 89) =

<h3>2928kg of ore are required</h3><h3 />

<em>Mass 80% sulfuric acid:</em>

12521 moles Titanium = 12521 moles H₂SO₄ * (100/89) = 14068.5 moles of H₂SO₄ are required.

In an excess of 50% =

14068.5 moles of H₂SO₄ are required * 1.5 = 21102.8 moles of H₂SO₄.

The mass is:

21102.8 moles of H₂SO₄ * (98g / mol) = 2068075g = 2068kg of sulfuric acid

That is in the 80%:

2068kg of sulfuric acid * (100/ 80) =

<h3>2585kg of the 80% H₂SO₄ solution are required</h3>
3 0
3 years ago
4. What is the main hydrocarbon component of natural gas? A. ethane
KIM [24]

Answer:

Q.4) C. Methane

Q.7) A. False

Q.8) A. True

7 0
2 years ago
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