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Ivahew [28]
1 year ago
7

Various nitrogen oxides, as well as sulfur oxides, contribute to acidic rainfall through complex reaction sequences. Nitrogen an

d oxygen combine during the high-temperature combustion of fuels in air to form nitrogen monoxide gas, which reacts with more oxygen to form nitrogen dioxide gas. In contact with water vapor, nitrogen dioxide forms aqueous nitric acid and more nitrogen monoxide. (a) Write balanced equations for these reactions.
Chemistry
1 answer:
dsp731 year ago
5 0

\begin{aligned}&\mathrm{N}_2(g)+\mathrm{O}_2(g) \longrightarrow 2 \mathrm{NO}(g) \\&2 \mathrm{NO}(g)+\mathrm{O}_2(g) \longrightarrow 2 \mathrm{NO}_2(g) \\&3 \mathrm{NO}_2(g)+\mathrm{H}_2 \mathrm{O}(g) \longrightarrow 2 \mathrm{HNO}_3(a q)+\mathrm{NO}(g)\end{aligned}

The above is balanced equations for the reactions mentioned in the question.

<h3>What is balanced equation?</h3>

A balanced reaction equation demonstrates atom conservation by displaying not only the several forms the reactants might take but also their amounts and quantities.

For instance, H + O H0 is the equation for the reaction between hydrogen and oxygen in its most basic form.

However, water is H₂O (the reaction proportion is 2:1, not 1:1), hence the equation needs an adjust: H₂ + O → H₂O.

However, due to the fact that oxygen occurs as diatomic molecules (O2), that is not yet the correct, final form. So put that: H2 + O2 H2O.

The amount of atoms on the left and right sides do not match, so this is not good enough. It is also not yet in balance. The coefficients must be changed in order for the right numbers to appear everywhere:

2H₂ + O₂ → 2H₂O

It works like this: on the left, there are 4 H atoms and 2 O atoms, and on the right, there are 4 H atoms and 2 O atoms.

Learn more about balanced equation

brainly.com/question/13103210

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A. Balance the following equation:
yanalaym [24]

Answer:

1.C+2H2-CH4

Explanation:

when we add two to hydrogen the product is equal to the reactant

7 0
3 years ago
12. How many molecules of glucose, C6H12O6, are present in a 152 g sample
ELEN [110]

Q.No. 12:

Answer:

                 5.08 × 10²³ Glucose Molecules

Solution:

Data Given:

                Mass of Glucose  =  152 g

                M.Mass of Glucose  =  180.156 g.mol⁻¹

Step 1: Calculate Moles of Glucose as,

                Moles  =  Mass ÷ M.Mass

Putting values,

                Moles  =  152 g ÷ 180.156 g.mol⁻¹

                Moles  =  0.8437 mol

Step 2: Calculate number of Glucose Molecules,

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of glucose molecules can be written as,

 Moles  =  Number of Glucose Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Glucose Molecules,

 Number of Glucose Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

 Number of Glucose Molecules  =  0.8437 mol × 6.022 × 10²³ Atoms.mol⁻¹

 Number of Glucose Molecules =  5.08 × 10²³ Glucose Molecules

______________________________________________

Q.No. 12: (A)

Answer:

                3.04 × 10²⁴ Carbon Atoms

Solution:

              The molecular formula of Glucose is C₆H₁₂O₆. This specifies that there are six carbon atoms in one molecule of Glucose.

Hence,  when,

               1 molecule of Glucose contain  =  6 atoms of Carbon

Then,

     5.08 × 10²³ Glucose Molecules will contain  =  X atoms of Carbon

Solving for X,

                     X =  5.08 × 10²³ molecules  × 6 atoms / 1 molecule

                     X  =  3.04 × 10²⁴ Carbon Atoms

______________________________________________

Q.No. 12: (B)

Answer:

                1.22 × 10²⁵ Atoms in total

Solution:

              The molecular formula of Glucose is C₆H₁₂O₆. This specifies that there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of Glucose. So, there are 24 atoms in one molecule of glucose

Hence,  when,

                    1 molecule of Glucose contain  =  24 atoms

Then,

          5.08 × 10²³ Glucose Molecules will contain  =  X atoms

Solving for X,

                     X =  5.08 × 10²³ molecules  × 24 atoms / 1 molecule

                     X  =  1.22 × 10²⁵ Atoms in total

______________________________________________

Q. No. 13

Answer:

                   1061.81 g of Aluminium

Solution:

Data Given:

                Number of F.Units  =  2.37 × 10²⁵

                A.Mass of Aluminium  =  26.98 g.mol⁻¹

                Mass of Aluminium  =  ?

Step 1: Calculate Moles of Aluminium,

                  Moles  =  Number of F.Units ÷ 6.022 × 10²³ F.Units.mol⁻¹

Putting value,

                  Moles  =   2.37 × 10²⁵ F.Units ÷ 6.022 × 10²³ F.Units.mol⁻¹

                  Moles  =  39.35 mol

Step 2: Calculate Mass of Aluminium as:

                  Moles  =  Mass ÷ A.Mass

Solving for Mass,

                  Mass  =  Moles × A.Mass

Putting values,

                  Mass  =  39.35 mol × 26.98 g.mol⁻¹

                  Mass  =  1061.81 g of Aluminium

8 0
3 years ago
State two causes of cracked and sore nipples during breastfeeding
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The biting and sucking of the baby when eating.
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3 years ago
How many molecules of water are needed to completely break apart a polymer that is 11 monomers long?
tankabanditka [31]
I believe the answer is 10
6 0
3 years ago
How many grams of sodium chloride must dissolve in 750.0 g of water to make a 0.50 molal solution?
AleksandrR [38]
Molality is defined as the number of moles of solute in 1 kg of solvent.
molality of solution to be prepared is 0.50 molal
this means that in 1000 g of water there should be 0.50 mol of NaCl
if 1000 g of water should contain - 0.50 mol 
then 750.0 g of water requires - 0.50 mol/kg x 0.750 kg = 0.375 mol
mass of NaCl in 0.375 mol - 58.5 g/mol x 0.375 mol = 21.9 g
therefore a mass of 21.9 g of NaCl is required 
7 0
3 years ago
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