It’s A .. I think I hope this helps !
From my understanding the correct answer would be phyical
Given data:
Mass of copper (m) = 20.0 g
Initial temperature of Copper (T1)= 25 C
Final temperature = T2
Heat absorbed by copper (Q) = 475 J
Specific heat of Copper (c) = 0.385 J/g C
Formula:
Q = mcΔT
= mc(T2-T1)
475 = 20*0.385*(T2-25)
62.08 = T2-25
T2 = 87.08 = 87.1 C
