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frutty [35]
2 years ago
12

Solve for x 6.58-8.36x=3.98x-27.33 Round to nearest hundred

Mathematics
2 answers:
ololo11 [35]2 years ago
7 0

Answer:

6.58-8.36x=3.98x-27.33

Collecting like terms

6.58+27.33=3.98x+8.36x

33.91=12.34x

33.91/12.34=12.34/12.34

x=2.75

Naddik [55]2 years ago
5 0

Answer:

x=2.75

Step-by-step explanation:

subtract 3.98x from both sides

6.58-8.36x=3.98x-27.33

6.58-3.98x-8.36x=27.33

subtract 6.58 from both sides

-3.98x-8.36x=27.33-6.58

add like terms:

-12.34x=-33.91

divide both sides by -12.34

x=3391/1234

x=2.75

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Line A passes through the points (10,6) qnd (2,15). Line B passes through the points (5,9) and (14,-1).
e-lub [12.9K]

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Line A equation = y=-9/8x+69/4

Line B equation = y=-10/9x+131/9

Step-by-step explanation:

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2 years ago
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klasskru [66]

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Step-by-step explanation:

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A sphere with a diameter of 30 inches is placed in a cube. The sphere touches the lateral faces
Nina [5.8K]

Answer:

a) 30 inches × 30 inches × 30 inches

b) 27,000 inches³

c) 14,130 inches³

d) 12,870 inches³

Step-by-step explanation:

Edge of the cube = diameter = 30 inches

Volume of cube = s³

30³ = 27000 inches³

Radius = 30/2 = 15

Volume of sphere:

(4/3) × 3.15 × 15³

14130 inches³

Difference:

27000 - 14130

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5 0
3 years ago
In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays.Find the probability that he did not hit a bounda
Margarita [4]

Answer:

The probability of NOT hitting a boundary is (4/5).

Step-by-step explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E =  \frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}

Here, number of favorable outcomes = 6

So, P(E)  = \frac{6}{30}  = \frac{1}{5}

⇒Probability of hitting a six is 1/5

Now, P(E)  + P(not E)  = 1

So, P(not hitting a boundary ) = 1  -  P(hitting a boundary)

= 1 - (1/5)  = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).

4 0
2 years ago
Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
Sphinxa [80]

Answer:

x=2.125

y=0

C=19.125

Step-by-step explanation:

To solve this problem we can use a graphical method, we start first noticing the restrictions x\geq 0 and  y\geq 0, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 8x+10y\leq 17 shown in purple, then we can plot the second one 11x+12y\leq 25 shown in the second plot in green.

The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.

So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.

3 0
2 years ago
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