Answer:
<h3>a.</h3>
- After it has traveled through 1 cm :
- After it has traveled through 2 cm :
<h3>b.</h3>
- After it has traveled through 1 cm :
- After it has traveled through 2 cm :
Explanation:
<h2>
a.</h2>
For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient the formula is:
where I is the intensity of the beam, is the incident intensity and x is the length of the material traveled.
For our problem, after travelling 1 cm:
After travelling 2 cm:
<h2>b</h2>
The optical density od is given by:
.
So, after travelling 1 cm:
After travelling 2 cm:
Answer:
The visible light frequency is 400 THz to 700 THz, approximately. A THz is a Terahertz, which is a unit of frequency equal to one trillion Hertz.
Answer:
Work done is 93.75J
Explanation:
Given mass, m = 30kg; Time = 5 seconds; force = 15N; u= 0
Acceleration, a = F/m ⇒ 15/30
⇒ 0.5ms
Displacement , s= ut+1/2at²
⇒ 0 +1/2 (0.5*5*5)
⇒ 0 + 1/2(0.5*25)
⇒ 0 + 1/2(12.5)
⇒ 0 + 6.25
⇒ 6.25m
work done = Fs=15*6.25= 93.75 J
Answer:
Spring's displacement, x = -0.04 meters.
Explanation:
Let the spring's displacement be x.
Given the following data;
Mass of each shrew, m = 2.0 g to kilograms = 2/1000 = 0.002 kg
Number of shrews, n = 49
Spring constant, k = 24 N/m
We know that acceleration due to gravity, g is equal to 9.8 m/s².
To find the spring's displacement;
At equilibrium position:
Fnet = Felastic + Fg = 0
But, Felastic = -kx
Total mass, Mt = nm
Fg = -Mt = -nmg
-kx -nmg = 0
Rearranging, we have;
kx = -nmg
Making x the subject of formula, we have;
Substituting into the formula, we have;
x = -0.04 m
Therefore, the spring's displacement is -0.04 meters.